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Updated: June 6, 2025
Let the same things be supposed as before; that is to say, let CO, perpendicular to CR, represent a portion of a wave the continuation of which in the crystal is IK, so that the piece C will be continued on along the straight line CI, while O comes to K. Now if one takes a second period of time equal to the first, the piece K of the wave IK will, in this second period, have advanced along the straight line KB, equal and parallel to CI, because every piece of the wave CO, on arriving at the surface CK, ought to go on in the crystal the same as the piece C; and in this same time there will be formed in the air from the point I a partial spherical wave having a semi-diameter IA equal to KO, since KO has been traversed in an equal time.
I find in my diaries accounts of conversations with such men as Bismarck, Camphausen, Delbr<u:>ck, Windthorst, Bennigsen, George von Bunsen, Lasker, Treitschke, Gneist, and others; but to take them up one after the other would require far too much space, and I must be content to jot down what I received from them wherever, in the course of these reminiscences, it may seem pertinent.
If you're so interested in improving the breed of horses by competitive contests, what 's the matter with that one where the prize is $5 for the team that can haul the heaviest load on a stoneboat, straight pulling? Pile on enough stones to build a house, pretty near, and the owner of the team, a young fellow with a face like Keats, goes "Ck! Ck! Ck!
Whence one sees that if the ray rC is inclined equally with RC, the line Cd will necessarily be equal to CD, because Ck is equal to CK, and Cg to CG. And in consequence Ii will be cut at E into equal parts by the line CM, to which DI and di are parallel.
You have furnished aid and comfort to the American soldier throughout the trying experiences of the last few days, and in accomplishing this worthy mission have spared yourself in nothing. The Division Commander wishes me to thank you for the Division and for himself. CK/T. Campbell King, Chief of Staff. Paris, December 17,1917. Commander Miss E, Booth, 120 W. 14th St., New York.
My life in that country and my reading since have steadily increased this respect and admiration. I noticed on the table a German book which he had just been reading, its author being my old friend Professor Hans Delbr<u:>ck of the Berlin University.
For since it together with the line NE is equal to the line CK, which is known, since DE is to AK in the proportion of the refraction, it appears that by deducting EN from CK the remainder will be equal to the curve NC. Similarly the waves that are folded back in reflexion by a concave spherical mirror can be found.
This stream we call North Mountain creek. the next stream in order is a creek which falls in on Lard. 21/2 miles higher; this is 15 yds. wide no water; a large village of the burrowing or barking squirrels on the Stard. side opposite it's entrance, hence the name Little dog Ck. that being the name by which the French Engages call this anamal. at three miles and at 10 ms. from hence still ascending 2 Small creek fall in on the Stard. side, no water. 51/2 miles higher a small river falls in on Lard. side this we called South Mountain creek as from it's direction it appeared to take it's rise in a range of Mountains lying in a S. Westerly direction from it's entrance distant 50 or 60 m.; this creek is 40 yards wide and discharges a handsome stream of water. it's bed is rockey with gravel and sand, the banks high and country broken it's bottom narrow and no timber.
I heard things in my head and ears that weren't sounding anywhere else. And all of a sudden tramp, tramp, tramp I heard the cop's footsteps. He stopped over there by the swinging electric light above the gate. I crouched down behind the iron bench. And my coat caught a twig on a bush and its crack ck was like a yell. I thought I'd die. I thought I'd scream. I thought I'd run. I thought I'd faint.
Now it must be noted that the same ellipse HME serves to find the refractions of any other ray which may be in the plane through RC and CK. Because every plane, parallel to the straight line HF, or TK, which will touch the spheroid, will touch it in this ellipse, according to the Lemma quoted a little before.
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