Vietnam or Thailand ? Vote for the TOP Country of the Week !
Updated: May 11, 2025
Supposing then, in the next figure, as previously, the surface of the crystal gG, the Ellipse GPg, and the line N; and CM the refraction of the perpendicular ray FC, from which it diverges by 6 degrees 40 minutes. Now let there be some other ray RC, the refraction of which must be found.
Since then the parallelogram Ki is that which touches all these spheroids, this same parallelogram will be precisely the continuation of the wave COoc in the crystal, when Oo has arrived at Kk, because it forms the termination of the movement and because of the quantity of movement which occurs more there than anywhere else: and thus it appears that the piece C of the wave COoc has its continuation at I; that is to say, that the ray RC is refracted as CI.
T three LP loop B bracket RC rocker C counter Supposing the figure to be executed to be the well-known "figure eight." It would be described as follows: R-F-O L-F-O. R-F-I L-F-I. R-B-O L-B-O. R-B-I L-B-I. By referring to the above table the skater can easily determine just what strokes are necessary to produce the figure properly.
For the rest, the position of this ellipse, with respect to the plane through the ray RC and through CK, is also given; from which it will be easy to find the position of CI, the refraction corresponding to the ray RC.
And, since a ray perpendicular to a plane, and coming from a very distant source of light, is nothing else, according to the precedent Theory, than the incidence of a portion of the wave parallel to that plane, I supposed the straight line RC, parallel and equal to AB, to be a portion of a wave of light, in which an infinitude of points such as RHhC come to meet the surface AB at the points AKkB. Then instead of the hemispherical partial waves which in a body of ordinary refraction would spread from each of these last points, as we have above explained in treating of refraction, these must here be hemi-spheroids.
As then, CK is to KO, so also is RC to CV. But KO is equal to N, and RC to CG: then as CK is to N so will CG be to CV. But as N is to CG, so, by construction, is CV to CD. Then as CK is to CG so is CG to CD. And because DI is parallel to CM, the conjugate diameter to CG, it follows that KI touches the Ellipse at I; which remained to be shown.
Let us suppose one of the faces of the crystal, in which let there be the Ellipse HDE, the centre C of which is also the centre of the spheroid HME in which the light spreads, and of which the said Ellipse is the section. And let the incident ray be RC, the refraction of which it is required to find.
They are in no respect up to sample which we keep pending a settlement of any differences which we might have in respects to this matter. Yours truly, L. FEINHOLZ. Dic LF to RC "What does that sucker mean, Mawruss?" Abe asked. "We ain't sent him no sample of them capes, Mawruss. We made 'em up according to his instructions, Mawruss. Ain't it?" Morris nodded solemnly and again Abe read the letter.
Word Of The Day
Others Looking