United States or Åland ? Vote for the TOP Country of the Week !
If one draws IP perpendicular to this DP, it will be the distance PS which will mark the apparent elevation of the point I. Let there be described on Gg a semicircle cutting CR at B, from which let BV be drawn perpendicular to Gg; and let N to GC be the proportion of the refraction in this section, as in Article 28.
He broadcast, tuned as broadly as possible, and went up and down the GC spectrum, repeating his warning painstakingly and listening without hope for a reply. He did find one spot on the dial where there was re-radiation of his message, as if from a tuned receiver. But he could not get a fix on it: nobody might be listening. He exhausted the normal communication pattern.
Again, if one turns the Crystal in such wise that an incident ray NO, of sunlight, which I suppose to be in the plane continued from GCFH, makes with GC an angle of 73 degrees and 20 minutes, and is consequently nearly parallel to the edge CF, which makes with FH an angle of 70 degrees 57 minutes, according to the calculation which I shall put at the end, it will divide itself at the point O into two rays, one of which will continue along OP in a straight line with NO, and will similarly pass out of the other side of the crystal without any refraction; but the other will be refracted and will go along OQ. And it must be noted that it is special to the plane through GCF and to those which are parallel to it, that all incident rays which are in one of these planes continue to be in it after they have entered the Crystal and have become double; for it is quite otherwise for rays in all other planes which intersect the Crystal, as we shall see afterwards.
But he settled down with the communicator to make the attempt. He called first on a GC wave-length and form. It was unlikely that blueskins would use general-communication bands to keep in touch with each other, but it had to be tried. He broadcast, as broadly tuned as possible, and went up and down the GC spectrum, repeating his warning painstakingly and listening without hope for a reply.
And, therefore, the time of the light along HF, supposing that the ray had been OF, would be equal to the time along BG in the interior of the medium C. But the time along AB is equal to the time along OH; therefore the time along OF is equal to the time along AB, BG. Again the time along FC is greater than that along GC; then the time along OFC will be longer than that along ABC. But AF is longer than OF, then the time along AFC will by just so much more exceed the time along ABC.
At the same place it was stated that GC was found to be 98,779 parts. And since the angle LCD is 45 degrees 20 minutes, being equal to GCS, the side LD is found to be 100,486: whence deducting ML 11,609 there will remain MD 88,877. Lemma which has been supposed.
The lad was squarely planted on his feet, with his legs a little apart; his back was slightly hollowed, his head thrown back, and both hands raised to support the rustic cup. There was a loosened fillet of wild flowers about his head, and his eyes, under their drooped lids, looked straight into the cup. On the base was scratched the Greek word ;aa;gD;gi;gc;ga, Thirst.
It was not satisfactory to be limited to broadcasts which might or might not be picked up, and were unlikely to be acknowledged. But he settled down with the communicator to make the attempt. He called first on a GC wave length and form. It was unlikely that blueskins would use general communication bands to keep in touch with each other, but it had to be tried.
Since then CI is the refraction of the radius BC, and DI is parallel to CM, VC must be to CD as N to GC, according to what has been demonstrated in Article 31.
To find the length of the line N, in proportion to CP, CS, CG, it must be determined by observations of the irregular refraction which occurs in this section of the crystal; and I find thus that the ratio of N to GC is just a little less than 8 to 5.
Word Of The Day