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Updated: June 3, 2025
That is, if you divide the current in amperes by the electromotive force in volts the quotient will give you the resistance in ohms. Or if you know what the electromotive force of the current is in volts and the resistance of the circuit is in ohms then you can find what the current flowing in the circuit is in amperes, thus: Volts E = Amperes, or = I Ohms R
In fact, the Machine-Gun Officer, Liaison Officer, and Padre had already gone, leaving their seniors to hold the fort till the last. The Signal Officer was down in the cellar, handing over ohms, ampères, short-circuits, and other mysterious trench-stores to his "opposite number."
That is, if you multiply the resistance of the circuit in ohms by the current in amperes the result will give you the electromotive force in volts. From this you will see that if you know the value of any two of the constants you can find the value of the unknown constant by a simple arithmetical process.
It consists of a primary coil of No. 20 B. and S. gauge cotton covered magnet wire wound on a core of soft iron wires while around the primary coil is wound a secondary coil of No. 30 magnet wire. Get a standard telephone induction coil that has a resistance of 500 or 750 ohms and this will cost you a couple of dollars. The Microphone Transformer.
It was proposed to string a steel-copper wire, the copper on which was to weigh 500 lb. to the mile. When complete, the wire was rather larger than No. 3, English gauge, but varied in diameter, some being as large as No. 1, and it averaged 525 lb. of copper per mile and = 1.5 ohms. The surface of this wire was, however, large. Dr.
The total energy of an electric current as it passes through a solution is distributed among three factors, first, its potential, which is measured in volts, and corresponds to what is called "head" in a stream of water; second, current strength, which is measured in amperes, and corresponds to the volume of water passing a cross-section of a stream in a given time interval; and third, the resistance of the conducting medium, which is measured in ohms.
The smallest size coils cost about $1.50 apiece and the mounting costs about $6 or $7 each. The A Battery Potentiometer. This device is simply a resistance like the rheostat described in connection with the preceding vacuum tube receiving sets but it is wound to 200 or 300 ohms resistance as against 1-1/2 to 6 ohms of the rheostat. It is, however, used as well as the rheostat.
It may be of interest, however, to mention some of its dimensions and electrical characteristics, quoting again from Mr. Clarke: "The field-magnet had eight solid cylindrical cores, 8 inches in diameter and 57 inches long, upon each of which was wound an exciting-coil of 3.2 ohms resistance, consisting of 2184 turns of No. 10 B. W. G. insulated copper wire, disposed in six layers.
This consists of: the grid leak; the chopper; the choke coil, and the key. The grid leak is connected in the lead from the grid to the aerial to keep the voltage on the grid at the right potential. It has a resistance of 5000 ohms with a mid-tap at 2500 ohms as shown at C. It costs $2.00. The chopper is simply a rotary interrupter driven by a small motor.
The generating machine is driven by a locomotive engine; the resistance of its field magnets is 5.68 ohms, and of the two armatures 33 ohms. The resistance of the two armatures of the receiving machine is 36.8 ohms, and the resistance of the line is 97 ohms; the generator and receiver field magnets are excited each by a separate machine.
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