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Having taken any point G in the line AK, and drawing the straight line IGL, its part GI will represent one of the incident rays, the refraction of which, GV, will then be found: and it is in this line that we must find the point D, one of those through which the curve DG ought to pass.
Let LG be a ray falling on the arc AK. Its refraction GV will be given by means of the tangent which will be drawn at the point G. Now in GV the point D must be found such that FD together with 3/2 of DG and the straight line GL, may be equal to FB together with 3/2 of BA and the straight line AL; which, as is clear, make up a given length.
"Otis' successor, John Waterly, of the democratic party, has just arrived. He brings with him papers and instructions in regard to proclamation of the Philippine Republic. "It is believed that Rev. Martin, Bishop of Cebú, will be transferred to the Archbishopric of Manila, and Rev. Nozaleda to Spain." Ibid., 2025. Taylor, 47 HS. Beginning on page 730. Taylor, 36 GV, Exhibit 1017. Taylor, 28 HS.
Now we know that the piece of wave which is incident on G, advances thence along the line GD, since GV is the refraction of the ray LG. Then during the time that this piece of wave has taken from G to D, the other piece which was at S has reached E, since GD, SE are equal.
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