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Updated: May 1, 2025
Let there be taken a plane passing through the ray RC and which is perpendicular to the plane of the ellipse HDE, cutting it along the straight line BCK; and having in the same plane through RC made CO perpendicular to CR, let OK be adjusted across the angle OCK, so as to be perpendicular to OC and equal to the line N, which I suppose to measure the travel of the light in air during the time that it spreads in the crystal through the spheroid HDEM. Then in the plane of the Ellipse HDE let KT be drawn, through the point K, perpendicular to BCK. Now if one conceives a plane drawn through the straight line KT and touching the spheroid HME at I, the straight line CI will be the refraction of the ray RC, as is easy to deduce from that which has been demonstrated in Article 36.
Inside the cabin, Scotty switched on his flashlight, took his slate, and wrote, "Thyl thnk we wnt bk to bot. We sty hr lng nuff thy fnd out we nt thr & cm bck lkng fr us. Thn we go up to bot." Rick nodded his understanding. It was good strategy, provided they timed it right. The frogmen would assume the boys had returned to the Water Witch when they went up through the murky layer.
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