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Cl :MnO = 71:86.9. After canceling the common factors, there remains 2Na S O :MnO = 316.4:86.9, and the factor for the conversion of thiosulphate into an equivalent of manganese dioxide is 86.9/316.4.
The reactions involved are: MnO + 4HCl > MnCl + 2H O + Cl Cl + 2KI > I + 2KCl I + 2Na S O > 2NaI + Na S O Assuming that the weight of thiosulphate corresponding to the volume of sodium thiosulphate solution used is known, what is the corresponding weight of manganese dioxide? From the reactions given above, the following proportions may be stated: 2Na S O :I = 316.4:253.9, I :Cl = 253.9:71,
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