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Then when the heterotypic division takes place and the number of chromosomes is halved, we shall have two spermatocytes with N-1 chromosomes from one of the first spermatocytes and one with N and one with N-1 from the other. Thus there will be three spermatozoa with N-1 chromosomes and one with N chromosomes, whereas we are supposed to find equal numbers with N and N-1 chromosomes.
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