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!Answer!: 20.08 cc. !Answer!: 5.70 cc. A sample of pyrolusite weighing 0.6000 gram is treated with 0.9000 gram of oxalic acid. What is the percentage of MnO , in the sample? !Answer!: 84.47%. A solution contains 50 grams of KHC O .H C O .2H O per liter. In the analysis of an iron ore containing 60% Fe O , a sample weighing 0.5000 gram is taken and the iron is reduced with sulphurous acid.
Sample IV. On titrating with hydrochloric acid, using phenolphthalein, 15.00 cc. were required. A new sample of the same weight required exactly 30 cc. of the same acid for neutralization, using methyl orange. In the analysis of a sample of KHC H O the following data are obtained: Weight sample = 0.4732 gram. NaOH solution used = 24.97 cc. 3.00 cc.
NaOH = 1 cc. of H PO solution of which 1 cc. will precipitate 0.01227 gram of magnesium as MgNH PO . Calculate the percentage of KHC H O . !Answer!: 88.67%. A one-gram sample of sodium hydroxide which has been exposed to the air for some time, is dissolved in water and diluted to exactly 500 cc.
NaOH solution; 1 cc. NaOH = 1.743 cc. KHC O .H C O .2H O solution; Normal value NaOH = 0.12. !Answer!: 4.885. Given the following data: 25 cc. of a hydrochloric acid, when standardized gravimetrically as silver chloride, yields a precipitate weighing 0.5465 gram. 24.35 cc. of the hydrochloric acid are exactly equivalent to 30.17 cc. of KHC O .H C O .2H O solution.
A student standardized a solution of NaOH and one of KMnO against pure KHC O .H C O .2H O and found the former to be 0.07500 N as an alkali and the latter exactly 0.1 N as an oxidizing agent. By coincidence, exactly 47.26 cc. were used in each standardization. Find the ratio of the oxalate used in the NaOH standardization to the oxalate used in the permanganate standardization. !Answer!: 1:1.
Calculate the percentage of potassium oxide in an impure sample of potassium carbonate from the following data: Weight of sample = 1.00 gram; HCl sol. used = 55.90 cc.; NaOH sol. used = 0.42 cc.; 1 cc. NaOH sol. = 0.008473 gram of KHC O .H C O .2H O; 2 cc. HCl sol. = 5 cc. NaOH sol. !Answer!: 65.68%. NaOH solution = 1.190 cc. HCl solution. !Answer!: 97.97%.
!Answer!: 1.152 grams. What weight of cream of tartar must have been taken for analysis in order to have obtained 97.60% KHC H O in an analysis involving the following data: NaOH used = 30.06 cc.; H SO solution used = 0.50 cc.; 1 cc. H SO sol. = 0.0255 gram CaCO ; 1 cc. H SO sol. = 1.02 cc. NaOH sol.? !Answer!: 2.846 grams.
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