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Updated: May 28, 2025
Let there be also given in the axis the point L and the thickness BA of the glass; and let it be required to find the other surface KDB, which receiving rays that are parallel to AB will direct them in such wise that after being again refracted at the given surface AK they will all be reassembled at the point L.
Whence it follows reciprocally that parallel rays falling on the surface KDB will be reassembled at the point L.
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