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Since the sums of the times along AK, KB, and along AC, CB are equal, if from the former sum one deducts the time along KB, and if from the other one deducts the time along RB, there will remain the time along AK as equal to the time along the two parts AC, CR. Consequently in the time that the light has come along AK it will also have come along AC and will in addition have made, in the medium from the centre C, a partial spherical wave, having a semi-diameter equal to CR. And this wave will necessarily touch the circumference KS at R, since CB cuts this circumference at right angles.
B TT RB RY, he will hear of something to his advantage, and may be assured that all will be once more forgiven. A B LLA entreats him to write." What, in the name of all that is most mysterious, does this mean! was my first thought after reading the advertisement.
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